13+6k-k^2=0

Solution for 13+6k-k^2=0 equation:

13+6k-k^2=0

We add all the numbers together, and all the variables

-1k^2+6k+13=0

a = -1; b = 6; c = +13;
Δ = b2-4ac
Δ = 62-4·(-1)·13
Δ = 88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{88}=\sqrt{4*22}=\sqrt{4}*\sqrt{22}=2\sqrt{22}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{22}}{2*-1}=\frac{-6-2\sqrt{22}}{-2}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{22}}{2*-1}=\frac{-6+2\sqrt{22}}{-2}
$